Note that the hidden cards of a player's opponents may affect the calculation of outs. For example, assume that a Texas hold 'em board looks like this after the third round: 5♠ K♦ 7♦ J♠, and that a player is holding A♦ 10♦. The player's current hand is just a high ace, which is not likely to win unimproved, so the player has a drawing hand. He has a minimum of seven outs for certain, called nut outs, because they will make his hand the best possible: those are the 2♦, 3♦, 4♦, 6♦, 8♦, 9♦, and Q♦ (which will give him an ace-flush with no possible better hand on the board) and the Q♣ and Q♥, which will give him an ace-high straight with no higher hand possible. The 5♦ and J♦ will also make him an ace-high flush, so those are possible outs since they give him a hand that is likely to win, but they also make it possible for an opponent to have a full house (if the opponent has something like K♠ K♣, for example). Likewise, the Q♠ will fill his ace-high straight, but will also make it possible for an opponent to have a spade flush. It is possible that an opponent could have as little as something like 7♣ 9♣ (making a pair of sevens); in this case even catching any of the three remaining aces or tens will give the player a pair to beat the opponent's, so those are even more potential outs. In sum, the player has seven guaranteed outs, and possibly as many as 18, depending on what cards he expects his opponents to have.
See also
Categories: Poker gameplay and terminology